Timeline for Does Heisenberg's uncertainty principle fail in the case of two-dimensional rigid rotor?
Current License: CC BY-SA 3.0
15 events
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Mar 17, 2018 at 20:25 | vote | accept | Phillip | ||
Jan 29, 2018 at 23:22 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Dec 28, 2017 at 7:26 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Nov 25, 2017 at 0:42 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Oct 21, 2017 at 7:37 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Jul 11, 2017 at 11:02 | history | tweeted | twitter.com/StackPhysics/status/884729635224694784 | ||
Mar 20, 2017 at 2:57 | comment | added | WillO | @ACuriousMind has given you the answer, but in case the helps to clarify it: The components of angular momentum in the $x$ and $y$ directions do not commute, so they cannot both be well-defined at the same moment. Therefore they certainly cannot both be zero. | |
Feb 8, 2017 at 14:45 | comment | added | Ruslan | @ZeroTheHero you can. It's just the equation in cylindrical coordinates after choosing $\psi(z)=\operatorname{const}.$ and removing the $\rho$-dependent factor. | |
Feb 8, 2017 at 13:56 | answer | added | Amara | timeline score: 2 | |
Feb 8, 2017 at 13:34 | comment | added | ZeroTheHero | Moreover, if you Schrödinger equation only contains $\varphi$, you can't use momentum $L^2$. To put it differently, $L^2$ is the basically the Laplacian in spherical coordinates, but your functions $e^{im\varphi}$ are not eigenfunctions of the Laplacian. | |
Feb 8, 2017 at 13:28 | history | edited | Qmechanic♦ | CC BY-SA 3.0 |
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Feb 8, 2017 at 13:28 | comment | added | Phillip | I am relatively new to this field of physics, so i would prefer if you forgave me for any mistakes that i made regarding the quantum mechanical formalism. | |
Feb 8, 2017 at 13:14 | comment | added | ACuriousMind♦ | "However, both values can only be the same if the components in the x and y direction are both equal to zero" - why? (Don't argue classically, show it in quantum mechanics!) | |
Feb 8, 2017 at 13:09 | review | First posts | |||
Feb 8, 2017 at 13:22 | |||||
Feb 8, 2017 at 13:09 | history | asked | Phillip | CC BY-SA 3.0 |