Skip to main content
added 1 character in body; edited tags; edited title
Source Link
Qmechanic
  • 213.1k
  • 48
  • 590
  • 2.3k

singularity Singularity of Coulomb s law

Coulomb's law says electrostatic field intensity varies as 1/r².i$1/r²$ i.e ha singularity at location of charge. now if a charge distribution is accumulation of many point charges.then then for a charged metallic sphere why do we get finite potential at surface???? it should hav been infinity.since since it is whwre charges are located. please answer as simply possible.

singularity of Coulomb s law

Coulomb's law says electrostatic field intensity varies as 1/r².i.e ha singularity at location of charge. now if a charge distribution is accumulation of many point charges.then for a charged metallic sphere why do we get finite potential at surface???? it should hav been infinity.since it is whwre charges are located please answer as simply possible.

Singularity of Coulomb s law

Coulomb's law says electrostatic field intensity varies as $1/r²$ i.e ha singularity at location of charge. now if a charge distribution is accumulation of many point charges. then for a charged metallic sphere why do we get finite potential at surface? it should hav been infinity. since it is whwre charges are located. please answer as simply possible.

Source Link
watson
  • 109
  • 6

singularity of Coulomb s law

Coulomb's law says electrostatic field intensity varies as 1/r².i.e ha singularity at location of charge. now if a charge distribution is accumulation of many point charges.then for a charged metallic sphere why do we get finite potential at surface???? it should hav been infinity.since it is whwre charges are located please answer as simply possible.