Timeline for Domain space of compatible and incompatible operators (observables)
Current License: CC BY-SA 3.0
13 events
| when toggle format | what | by | license | comment | |
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| May 19, 2020 at 0:16 | vote | accept | Arkya | ||
| May 19, 2020 at 0:15 | comment | added | Arkya | Thanks. After revisiting this question, I realize I had misunderstood what was being said in the quoted excerpt. | |
| May 17, 2020 at 23:19 | answer | added | user87745 | timeline score: 2 | |
| May 17, 2020 at 23:11 | comment | added | user87745 | If you're not already assuming that the operators are defined on the same domain, vanishing commutator won't help you much because the commutator would only be defined on some type of an intersection of the domains and its vanishing nature would only be applicable in that intersection. So, I don't see how a vanishing commutator can help us claim that the operators share the same domain. | |
| May 17, 2020 at 23:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jan 16, 2020 at 19:03 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Sep 18, 2019 at 3:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Aug 1, 2019 at 19:47 | history | edited | Qmechanic♦ |
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| Aug 1, 2019 at 19:02 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Dec 9, 2017 at 10:04 | answer | added | Mahathi Vempati | timeline score: 2 | |
| Feb 4, 2017 at 14:31 | comment | added | Arkya | Yes, but are we assuming here that the operators are defined on the same domain space? They should, I guess.. | |
| Feb 4, 2017 at 14:29 | comment | added | ACuriousMind♦ | Assuming the observables are defined on the same space, why would you need commutativity to say that their eigenkets span the same space? You can just apply the spectral theorem to each separately, no? | |
| Feb 4, 2017 at 14:23 | history | asked | Arkya | CC BY-SA 3.0 |