Timeline for Time-reversal for Heisenbergs equation of motion
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
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| Feb 3, 2017 at 10:43 | comment | added | Daniel | In case anyone else runs into this problem, there are more mistakes above, although I haven't carefully checked it. Probably $T\dot a T^{-1}=-\dot a$ as well. | |
| Jan 17, 2017 at 17:09 | comment | added | udrv | You have $a = \sqrt{\omega/2\hbar}\left(q +(i/\omega) p \right) $ and $TaT^{-1} = \sqrt{\omega/2\hbar}\left( TqT^{-1} - (i/\omega) TpT^{-1} \right] = \sqrt{\omega/2\hbar}\left(q - (i/\omega) (-p) \right] = a$, not $TaT^{-1} = a^\dagger$. Similarly for $a^\dagger$. | |
| Jan 16, 2017 at 16:52 | history | asked | Daniel | CC BY-SA 3.0 |