From this law: $2\pi r=n\lambda$. if the radius of the atomic orbit increases the wavelength of the electron will increase.

And if the wavelength increase the energy will decreaces due to: $E=hf$.

But actually the energy of electron increases if energy level increases!!

From this law: $2\pi r=n\lambda$. if the radius of the atomic orbit increases the wavelength of the electron will increase.

And if the wavelength increase the energy will decreases due to: $E=hf$.

But actually the energy of electron increases if energy level increases!!

from this law: 2pi r=n*lambda. if the radius of the atomic orbit increases the wavelength of the electron will increase. and if the wavelength increase the energy will decreaces due to: E=hv. but actually the energy of electron increases if energy level increases!!

From this law: $2\pi r=n\lambda$. if the radius of the atomic orbit increases the wavelength of the electron will increase.

And if the wavelength increase the energy will decreaces due to: $E=hf$.

But actually the energy of electron increases if energy level increases!!

from this law: 2pir=n*lambda. if the radius of the atomic orbit increases the wavelength of the electron will increase. and if the wavelength increase the energy will decreaces due to: E=hv. but actually the energy of electron increases if energy level increases!!

from this law: 2pi r=n*lambda. if the radius of the atomic orbit increases the wavelength of the electron will increase. and if the wavelength increase the energy will decreaces due to: E=hv. but actually the energy of electron increases if energy level increases!!