Ds=dq/t.... Here, as the process is adiabatic it implies that there is no exchange of heat energy... So change in heat that is dq would b zero.... So accordingly in the eqn if dq is zero.... So ultimately ds is also zero.... This implies change in entropy

$\Delta s=\delta q/t$. Here, as the process is adiabatic it implies that there is no exchange of heat energy. So change in heat that is $\delta q$ would be zero. So accordingly in the equation if $\delta q$ is zero. So ultimately $ds$ is also zero. This implies a change in entropy.