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Dec 28, 2016 at 20:23 comment added JMLCarter Actually it's better to delete " Photons experience time dilation as they leave a gravitational well, when they get into the observer's frame of reference they will have been red shifted.". I think it has a sign wrong too. It is easier to look at it the other way around; photons are invariant as they ascend, but the observer's clock outside the gravity well is faster, so they appear red-shifted on arrival. sorry for that error.
Dec 28, 2016 at 20:07 comment added JMLCarter You are correct, it is wrong. Not sure I understand why you think there would be no redshift well enough to pinpoint what is wrong Photons experience time dilation as they leave a gravitational well, when they get into the observer's frame of reference they will have been red shifted. (NB: There are different causes of redshift. Photons also experience red-shift due to the relative velocity of the source and observer. This is a different effect.)
Dec 28, 2016 at 19:59 comment added Copernic You wrote "So for them other frames of reference seem faster" If that were true there would be no gravitational Redshift, wrong?
Dec 28, 2016 at 19:55 comment added JMLCarter I should say "as you move from one orbit to another that is nearer the black hole", rather than "as you approach".
Dec 28, 2016 at 19:42 comment added JMLCarter Time is slower in the dilated time frame, for the landing party. So for them objects in other frames of reference away from the black hole seem faster. As you approach the black hole you are changing you frame of reference.
Dec 28, 2016 at 19:40 comment added Copernic A faster movement in a dilated time frame??? Shouldn't movement be slower or at least equal following proper time or relativity and equivalence principles?
Dec 28, 2016 at 19:37 history answered JMLCarter CC BY-SA 3.0