Skip to main content
6 events
when toggle format what by license comment
Dec 28, 2016 at 1:37 answer added Sciencetastic timeline score: 0
Dec 27, 2016 at 21:45 history edited Qmechanic
edited tags
Dec 27, 2016 at 18:35 comment added hsnee Since gravity is a conservative force, it shouldn't matter what path you choose to calculate work. i.e. using either $|{\vec{B} - \vec{A}}|$ or the circular path should give the same result.
Dec 27, 2016 at 18:31 history edited auden CC BY-SA 3.0
added 38 characters in body; edited tags
Dec 27, 2016 at 18:29 review First posts
Dec 27, 2016 at 19:18
Dec 27, 2016 at 18:25 history asked Suraz Basnet CC BY-SA 3.0