Timeline for Momentum state of a particle
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
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| Feb 13, 2017 at 19:36 | vote | accept | CommunityBot | ||
| Feb 13, 2017 at 19:36 | |||||
| Jan 15, 2017 at 15:28 | vote | accept | CommunityBot | ||
| Jan 16, 2017 at 6:11 | |||||
| Jan 1, 2017 at 11:32 | history | edited | AccidentalFourierTransform | CC BY-SA 3.0 |
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| Dec 26, 2016 at 17:16 | history | edited | coconut | CC BY-SA 3.0 |
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| Dec 26, 2016 at 16:43 | comment | added | coconut | I have added a paragraph explaining why these definitions make sense. Maybe that helps you | |
| Dec 26, 2016 at 16:42 | history | edited | coconut | CC BY-SA 3.0 |
Added a clarification about the definitions of position and momentum representation
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| Dec 26, 2016 at 16:35 | history | edited | coconut | CC BY-SA 3.0 |
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| Dec 26, 2016 at 16:29 | comment | added | coconut | I defined the position and momentum representations and then showed that the Fourier transform takes one into the other. I thought that was what you were asking. I mean, I can't tell you why the Fourier transform gives you the momentum space from the position one if we don't have a definition for them to begin with. I'll edit to make this clearer | |
| Dec 26, 2016 at 16:22 | comment | added | user56224 | In your explanation you already applied what I am asking for. I didn't ask for the momentum representation of the position operator etc. | |
| Dec 25, 2016 at 23:55 | history | edited | coconut | CC BY-SA 3.0 |
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| Dec 25, 2016 at 23:37 | history | edited | coconut | CC BY-SA 3.0 |
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| Dec 25, 2016 at 23:25 | history | answered | coconut | CC BY-SA 3.0 |