Timeline for Momentum state of a particle
Current License: CC BY-SA 3.0
16 events
| when toggle format | what | by | license | comment | |
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| Feb 13, 2017 at 21:00 | vote | accept | CommunityBot | ||
| Feb 13, 2017 at 19:36 | vote | accept | CommunityBot | ||
| Feb 13, 2017 at 21:00 | |||||
| Feb 13, 2017 at 19:36 | vote | accept | CommunityBot | ||
| Feb 13, 2017 at 19:36 | |||||
| Jan 16, 2017 at 6:12 | vote | accept | CommunityBot | ||
| Feb 13, 2017 at 19:36 | |||||
| Jan 16, 2017 at 6:12 | vote | accept | CommunityBot | ||
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| Jan 16, 2017 at 6:11 | vote | accept | CommunityBot | ||
| Jan 16, 2017 at 6:12 | |||||
| Jan 15, 2017 at 15:28 | vote | accept | CommunityBot | ||
| Jan 16, 2017 at 6:11 | |||||
| Jan 15, 2017 at 12:12 | vote | accept | CommunityBot | ||
| Jan 15, 2017 at 15:28 | |||||
| Dec 26, 2016 at 16:05 | comment | added | user56224 | Aren't there uncoutable many alternative possibilities of linear transformations to other representations? My question is, why do we choose the specific form above? | |
| Dec 26, 2016 at 6:42 | history | edited | Qmechanic♦ |
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| Dec 25, 2016 at 23:51 | answer | added | Frotaur | timeline score: 4 | |
| Dec 25, 2016 at 23:25 | answer | added | coconut | timeline score: 1 | |
| Dec 25, 2016 at 22:40 | answer | added | JamalS | timeline score: 1 | |
| Dec 25, 2016 at 22:13 | history | edited | JamalS | CC BY-SA 3.0 |
added 17 characters in body
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| Dec 25, 2016 at 22:12 | comment | added | JamalS | Well, what else would it be? If you want to go from position space to momentum space (or equivalently time to frequency) then you perform a Fourier transform. | |
| Dec 25, 2016 at 22:07 | history | asked | user56224 | CC BY-SA 3.0 |