Timeline for Will any charge flow in this circuit?
Current License: CC BY-SA 3.0
10 events
when toggle format | what | by | license | comment | |
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Dec 14, 2016 at 15:37 | comment | added | MrAP | I don't know.I am confused. | |
Dec 14, 2016 at 12:18 | comment | added | user1583209 | Do you agree that there is current flowing in the circuit which I linked in the answer? | |
Dec 14, 2016 at 12:17 | comment | added | user1583209 | I only wrote this to make clear the direction of current flow. Yes, {2,5} and {1,4} are equi-potent in theory. However in practice the connector from 1 to 4 and the one from 2 to 5 does have some small resistance (much smaller than the ones you have in the circuit). Therefore in practice you will have a small voltage between 1 and 4; and between 2 and 5. | |
Dec 14, 2016 at 11:57 | comment | added | MrAP | You wrote that "Current will flow between A and B split over all possible paths, in your case you have three paths: 1-2-5, 1-4-5, 1-4-3-2-5" but {2,5},{1,4},{1,4},{2,5} respectively are all equi-potent. I do not see why current should flow in the whole circuit. | |
Dec 14, 2016 at 11:33 | comment | added | user1583209 | I mean that this is certainly not a sufficient condition for having no current through the whole circuit. As I tried to make clear in my answer there are three paths along which there is a potential difference so that current will flow along those paths. Also take a look at the link in my answer which is exactly the same circuit you have here. | |
Dec 14, 2016 at 11:24 | comment | added | MrAP | You said"It does not matter whether you have the same potential somewhere in your circuit". What do you mean by this? | |
Dec 14, 2016 at 11:10 | comment | added | user1583209 | Corrected zero->same. Does not change anything on the result. | |
Dec 14, 2016 at 11:09 | history | edited | user1583209 | CC BY-SA 3.0 |
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Dec 14, 2016 at 11:09 | comment | added | MrAP | I said in the question that points having same potential have zero potential difference. I did not talk about zero potential. | |
Dec 14, 2016 at 11:04 | history | answered | user1583209 | CC BY-SA 3.0 |