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Dec 15, 2016 at 0:16 comment added ZHANG Juenjie Hello. but why it must be anti-symmetric under the exchange of the fermions. This is on Feynman Physics lectures, and I guess that we know the result and then constructed the wave function this way,
Dec 14, 2016 at 8:46 comment added Andrey Feldman @ZHANGJuenjie Pauli principle is just a consequence of ant-symmetry of fermionic wave functions. Let's consider the wave function of two fermions $\Psi(x_1, x_2)$. It must be anti-symmetric under the exchange of the fermions, thus $\Psi(x_1, x_2)=\Psi_1(x_1) \Psi_2(x_2)-\Psi_1(x_2) \Psi_2(x_1)$. This implies that $\Psi(x_1,x_2)=0$ if the fermions are in the same state.
Dec 14, 2016 at 8:31 comment added ZHANG Juenjie I just did a very rough scratch of that chapter. It seems that it mainly explains the reason why some types of particles cannot be constructed while however it doesn't say the reason of Pauli exclusion principle.
Dec 14, 2016 at 8:19 comment added ZHANG Juenjie Well, for this I also know and it is also in Peskin & Schroeder chapter 2. But this only says that for fermions it should be the anti-commutation relations but it doesn't say anything about the pauli exclusion principle.
Dec 14, 2016 at 6:40 history answered Andrey Feldman CC BY-SA 3.0