It depends on the dimensionality of the space one works with. In $2D$2d, the kinetic term that you presented appears after the integration over 4 Grassmann coordinates in the expression $\int \mathrm{d} \ \sigma^2 \mathrm{d} \ \theta^4 K(\Phi, \overline{\Phi})$$\int \mathrm{d}^2 \sigma \ \mathrm{d}^4 \theta K(\Phi, \overline{\Phi})$ which means $\cal{N}=2$. Perhaps it is the reason of your confusion?