Timeline for How will the (anti)commutation relation between two different fermion fields look like? [duplicate]
Current License: CC BY-SA 3.0
16 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 9, 2020 at 21:45 | history | closed |
tparker GiorgioP-DoomsdayClockIsAt-90 ZeroTheHero BioPhysicist stafusa |
Duplicate of Fermions, different species and (anti-)commutation rules | |
| Feb 5, 2020 at 4:00 | review | Close votes | |||
| Feb 9, 2020 at 21:45 | |||||
| Dec 5, 2016 at 11:56 | comment | added | Prof. Legolasov | @FraSchelle np, its just that I thought you misinterpreted my position in the argument, sorry :) | |
| Dec 5, 2016 at 11:40 | comment | added | FraSchelle | @SolenodonParadoxus Because you were part of the discussion, and the OP is automatically informed of a new comment. So I informed both of you of this comment. Sorry for the possible spam indeed. | |
| Dec 2, 2016 at 13:05 | comment | added | Prof. Legolasov | @FraSchelle the only thing that remains a mystery to me is why you address your comment to me when I clearly agree (you probably meant to address it to OP). | |
| Dec 2, 2016 at 12:35 | comment | added | FraSchelle | @SolenodonParadoxus $\alpha$ and $\beta$ are not defined in your question. You are thus free to define them the way you want, the rule will be the same. You can even suppose $\alpha = {\alpha_{1},\alpha_{2}, ...}$ if you wish, and $\delta_{\alpha,\beta}=\delta_{\alpha_{1},\beta_{1}}\delta_{\alpha_{2},\beta_{2}}...$ In short, the indices can be used in any way you want in order to distinguish the two fermion fields (spin up, spin down, brother and sister, blue and green, whatever and co, ... ). So the answer to your question is already there, in the Kronecker's notation :-) | |
| Dec 2, 2016 at 12:04 | vote | accept | SRS | ||
| Dec 2, 2016 at 11:16 | comment | added | Prof. Legolasov | @SRS different entries of the column vector $\psi$ are also different quantum fields. We only write them together because they form a Lorentz multiplet (that is, the Lorentz transformation for one of the entries depend on the values of all other entries). Btw I upvoted your question, I think it is perfectly reasonable to ask, especially if you are confused. | |
| Dec 2, 2016 at 8:05 | comment | added | SRS | @SolenodonParadoxus Isn't $\alpha,\beta$ label the indices of the elements/entries of the column vector $\psi$ and elements of the row vectors of $\bar{\psi}$? When I say, $\psi^1$ and $\psi^2$ I talk about two different fields, say electron and muon. | |
| Dec 2, 2016 at 5:17 | comment | added | Prof. Legolasov | @SRS that's exactly FraSchelle's point, I believe. Spinor indices label different fermionic degrees of freedom just as $(1)$ and $(2)$ do! | |
| Dec 1, 2016 at 21:00 | comment | added | SRS | @FraSchelle $\alpha,\beta$ are not fermion type label. They are spinor indices for a given fermion field $\psi$. | |
| Dec 1, 2016 at 13:29 | comment | added | FraSchelle | @Qmechanic Curiously, the question is answered in the question itself: the non-specified $\alpha$ and $\beta$ can be used for different fermion fields. If the OP had understood her notation, she would not have asked ... | |
| Dec 1, 2016 at 13:28 | answer | added | akhmeteli | timeline score: 2 | |
| Dec 1, 2016 at 9:26 | answer | added | Prof. Legolasov | timeline score: 2 | |
| Nov 30, 2016 at 11:22 | comment | added | Qmechanic♦ | 1. anticommutation. 2. zero. Related: physics.stackexchange.com/q/17893/2451 | |
| Nov 30, 2016 at 11:04 | history | asked | SRS | CC BY-SA 3.0 |