# Return to Answer

 3 Rollback to Revision 1 edited May 10 '17 at 14:48 Physicsmainland 122 bronze badges You have significantly over complicated the situation. List item - N/C ~ N/Kg So there must be an analogous quantity for ε. Where k=(4πϵ0)^-1 Therefore there must be an analog G=(4π@)^-1. x = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a} As for the positive negative issue it really isn't the permativity has no direction. The direction is determined by the charge, and the mass. It just happens there is only one possibility for mass... or is there? Why given all the parallels does electricity have an anti particle. You have significantly over complicated the situation. List item - N/C ~ N/Kg So there must be an analogous quantity for ε. Where k=(4πϵ0)^-1 Therefore there must be an analog G=(4π@)^-1. x = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a} As for the positive negative issue it really isn't the permativity has no direction. The direction is determined by the charge, and the mass. It just happens there is only one possibility for mass... or is there? Why given all the parallels does electricity have an anti particle. You have significantly over complicated the situation. List item - N/C ~ N/Kg So there must be an analogous quantity for ε. Where k=(4πϵ0)^-1 Therefore there must be an analog G=(4π@)^-1. As for the positive negative issue it really isn't the permativity has no direction. The direction is determined by the charge, and the mass. It just happens there is only one possibility for mass... or is there? Why given all the parallels does electricity have an anti particle. 2 added 2 characters in body edited May 10 '17 at 14:45 Physicsmainland 122 bronze badges You have significantly over complicated the situation. List item - N/C ~ N/Kg So there must be an analogous quantity for ε. Where k=(4πϵ0)^-1 Therefore there must be an analog G=(4π@)^-1. x = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a} As for the positive negative issue it really isn't the permativity has no direction. The direction is determined by the charge, and the mass. It just happens there is only one possibility for mass... or is there? Why given all the parallels does electricity have an anti particle. You have significantly over complicated the situation. List item - N/C ~ N/Kg So there must be an analogous quantity for ε. Where k=(4πϵ0)^-1 Therefore there must be an analog G=(4π@)^-1. As for the positive negative issue it really isn't the permativity has no direction. The direction is determined by the charge, and the mass. It just happens there is only one possibility for mass... or is there? Why given all the parallels does electricity have an anti particle. You have significantly over complicated the situation. List item - N/C ~ N/Kg So there must be an analogous quantity for ε. Where k=(4πϵ0)^-1 Therefore there must be an analog G=(4π@)^-1. x = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a} As for the positive negative issue it really isn't the permativity has no direction. The direction is determined by the charge, and the mass. It just happens there is only one possibility for mass... or is there? Why given all the parallels does electricity have an anti particle. 1 answered Nov 28 '16 at 21:34 Physicsmainland 122 bronze badges You have significantly over complicated the situation. List item - N/C ~ N/Kg So there must be an analogous quantity for ε. Where k=(4πϵ0)^-1 Therefore there must be an analog G=(4π@)^-1. As for the positive negative issue it really isn't the permativity has no direction. The direction is determined by the charge, and the mass. It just happens there is only one possibility for mass... or is there? Why given all the parallels does electricity have an anti particle.