Timeline for Why do excited states decay if they are eigenstates of Hamiltonian and should not change in time?
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
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| Feb 15, 2018 at 14:52 | history | bounty ended | Emilio Pisanty | ||
| Feb 8, 2018 at 16:07 | history | edited | AccidentalFourierTransform | CC BY-SA 3.0 |
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| Dec 8, 2016 at 3:27 | vote | accept | Abhay Srivastav | ||
| Dec 8, 2016 at 3:27 | vote | accept | Abhay Srivastav | ||
| Dec 8, 2016 at 3:27 | |||||
| Nov 30, 2016 at 9:34 | comment | added | valerio | Though this answer is correct (+1), I think that when reading it some people will think that you need some kind of source (charge or current) in order to have an interaction with the EM field, when instead there will be interaction also in absence of sources because of quantum fluctuations in the EM field ground state (vacuum state). Maybe it is worth mentioning this. | |
| Nov 28, 2016 at 22:06 | comment | added | AccidentalFourierTransform | @AbhaySrivastav your welcome, I'm glad I could help :-) in the case of atomic phenomena, other contributions come from: electrons interacting with other electrons; the spin of the nucleus interacting with the spin of the electrons; relativistic corrections (due to $E^2=p^2+m^2$ instead of $E=\frac{p^2}{2m}$). There are more contributions, such as the weak force, but these are truly negligible and nobody considers them to be relevant at all. | |
| Nov 28, 2016 at 21:02 | comment | added | Abhay Srivastav | That was helpful thanks. Just wondering apart from the electromagnetic field what other things will contribute to the Hamiltonian in this case? | |
| Nov 28, 2016 at 19:56 | history | edited | AccidentalFourierTransform | CC BY-SA 3.0 |
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| Nov 28, 2016 at 16:52 | history | edited | AccidentalFourierTransform | CC BY-SA 3.0 |
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| Nov 28, 2016 at 14:55 | history | answered | AccidentalFourierTransform | CC BY-SA 3.0 |