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Nov 17, 2016 at 16:32 comment added jac effron Thanks. First time I didn't quiet catch your answer. Now I got it. again thanks for your quick reply.
Nov 17, 2016 at 15:18 comment added Michael Seifert I'm not sure what you mean. I did assume the light rays were moving at zero vertical velocity according to an external frame: $dz_L/dt = 0$. I also assumed that the elevator was moving at a non-zero (but constant) velocity with respect to the external frame ($dz_E /dt = v = \text{const.}$) The point is that the vertical velocity of the light ray with respect to the elevator floor will change if and only if there is a change in the velocity of the elevator as measured in the external frame.
Nov 17, 2016 at 15:10 comment added jac effron You didn't notice that I mentioned light rays were entering from outside a source whose vertical velocity is zero with respect to an outside frame of reference. Where's the vertical velocity of elevator isn't zero with respect to the same frame.
Nov 17, 2016 at 14:55 history answered Michael Seifert CC BY-SA 3.0