Timeline for A spontaneous wavefunction collapse thought experiment
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
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| Apr 13, 2017 at 12:40 | history | edited | CommunityBot |
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| Nov 5, 2016 at 19:03 | comment | added | Prof. Legolasov | The interaction happens through the EM field. Photons are quanta of the EM field. | |
| Nov 5, 2016 at 0:00 | vote | accept | Shing | ||
| Nov 4, 2016 at 23:23 | answer | added | knzhou | timeline score: 4 | |
| Nov 4, 2016 at 23:09 | comment | added | Shing | @knzhou I do not understand the spontaneous emission mechanism. I basically assume it does not take any interaction. Would you mind answering it? | |
| Nov 4, 2016 at 23:04 | comment | added | knzhou | The point is that spontaneous emission is an interaction; the atom is always interacting with the (quantum) electromagnetic field via an interaction term in the Hamiltonian, whether or not the classical macroscopic field value is nonzero. | |
| Nov 4, 2016 at 23:02 | comment | added | Shing | @knzhou There is not necessarily a electromagnetic field in the experiment, and the detector can be far away. Or rather, if a excited state will never emit a photon without electromagnetic field? (I read that the atom will spontaneously emit a photon.) | |
| Nov 4, 2016 at 22:56 | comment | added | knzhou | I'm not sure what the question is here. The atom interacts with the electromagnetic field, which is then detected by the detector; it's pretty much a totally standard measurement. What is supposed to be "spontaneous"? | |
| Nov 4, 2016 at 22:56 | history | edited | Shing | CC BY-SA 3.0 |
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| Nov 4, 2016 at 22:50 | history | asked | Shing | CC BY-SA 3.0 |