Timeline for Is Schwinger's derivation of the two classes bosons and fermions a no-go theorem for supersymmetry?
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Nov 4, 2016 at 1:10 | comment | added | CGH | "spin statistic" means either bosonic or ferminic. A scalar field is bosonics, with spin 0. Both the LHS and the RHS of the transformation $\delta_\xi A=\sqrt{2} \xi^\alpha \psi_\alpha$ are spin 0 fields and none of them is a grassmannian variable, as expected. | |
Nov 3, 2016 at 18:57 | comment | added | user7154 | When you say "spin statistic", I guess you mean "transforms as" so that $\delta_{\xi}A=\sqrt{2}\xi^{\alpha}\psi_{\alpha}$ and both sides of the formula are scalars? | |
Nov 2, 2016 at 0:45 | history | answered | CGH | CC BY-SA 3.0 |