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Oct 31, 2016 at 12:34 comment added Chet Miller Actually, that's not the equation for the change in internal energy. Look it up in a Thermo book. It is $$dU=C_vdT-\left[P-T\left(\frac{\partial P}{\partial T}\right)_V\right]dV$$I suggest you check out the detailed development in Transport Phenomena by Bird, Stewart, and Lightfoot.
Oct 31, 2016 at 7:08 comment added Frysen Ahh.. I see. But if I dont make this assumption, then we have: $$ \varphi(T) = \int_0^T c_v(T) \, dT = \int_0^T c_p(T) \, dT - \int_0^V p(V) \, dV $$ ?
Oct 31, 2016 at 2:07 history answered Chet Miller CC BY-SA 3.0