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Qmechanic ♦
Qmechanic ♦
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I have the following question

enter image description here

And I have the formula for finding the pressure difference which is as follows:
P(below) = P(above) + ρgh
$$P(below) = P(above) + ρgh $$ And since they provide the information that it is vacuum, then Patm > Pabs.

Here is the solution:
enter image description here

I don't really understand why it is minus ρgh and I'm confused how to use the fact that it is vacuum. Also, what can we usually consider P(below) and P(above)?

I have the following question

enter image description here

And I have the formula for finding the pressure difference which is as follows:
P(below) = P(above) + ρgh
And since they provide the information that it is vacuum, then Patm > Pabs.

Here is the solution:
enter image description here

I don't really understand why it is minus ρgh and I'm confused how to use the fact that it is vacuum. Also, what can we usually consider P(below) and P(above)?

I have the following question

enter image description here

And I have the formula for finding the pressure difference which is as follows:
$$P(below) = P(above) + ρgh $$ And since they provide the information that it is vacuum, then Patm > Pabs.

Here is the solution:
enter image description here

I don't really understand why it is minus ρgh and I'm confused how to use the fact that it is vacuum. Also, what can we usually consider P(below) and P(above)?

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Jack
Jack
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Finding the pressure in vacuum

I have the following question

enter image description here

And I have the formula for finding the pressure difference which is as follows:
P(below) = P(above) + ρgh
And since they provide the information that it is vacuum, then Patm > Pabs.

Here is the solution:
enter image description here

I don't really understand why it is minus ρgh and I'm confused how to use the fact that it is vacuum. Also, what can we usually consider P(below) and P(above)?