Timeline for Is there a formula for the rotation vector in terms of the angular velocity vector?
Current License: CC BY-SA 4.0
32 events
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| S Apr 8, 2020 at 13:14 | history | suggested | CommunityBot | CC BY-SA 4.0 |
the formula as given has a wrong sign see (Page 41) and the link is broken http://www.ladispe.polito.it/corsi/Meccatronica/02JHCOR/2011-12/Slides/Shuster_Pub_1993h_J_Repsurv_scan.pdf
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| Apr 8, 2020 at 8:20 | review | Suggested edits | |||
| S Apr 8, 2020 at 13:14 | |||||
| Jul 5, 2017 at 11:48 | answer | added | Damien | timeline score: 1 | |
| Apr 13, 2017 at 12:40 | history | edited | CommunityBot |
replaced http://physics.stackexchange.com/ with https://physics.stackexchange.com/
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| Nov 29, 2016 at 1:25 | comment | added | Keshav Srinivasan | @fibonatic Thanks, I didn't know that. | |
| Nov 29, 2016 at 1:17 | comment | added | fibonatic | The quoted formula can also be written into a "simpeler" form, using $\vec{\alpha}=\theta\,\vec{n}$, with $\theta$ the magnitude of $\vec{\alpha}$ and $\vec{n}$ a unit vector pointing into the same direction as $\vec{\alpha}$. In this case the angular velocity can also be written as, $\vec{\omega}=\dot{\theta}\,\vec{n}+\sin\theta\,\dot{\vec{n}}+(1-\cos\theta)\,\vec{n}\times\dot{\vec{n}}$. But this does not help to answer your question, just thought that you might find it relevant. | |
| S Oct 31, 2016 at 10:03 | history | bounty ended | CommunityBot | ||
| S Oct 31, 2016 at 10:03 | history | notice removed | CommunityBot | ||
| Oct 27, 2016 at 12:02 | history | edited | Keshav Srinivasan | CC BY-SA 3.0 |
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| Oct 26, 2016 at 4:29 | history | edited | Keshav Srinivasan | CC BY-SA 3.0 |
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| Oct 26, 2016 at 4:23 | history | edited | Keshav Srinivasan | CC BY-SA 3.0 |
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| Oct 26, 2016 at 3:07 | answer | added | Selene Routley | timeline score: 1 | |
| Oct 26, 2016 at 2:30 | comment | added | Selene Routley | FYI the formula you quote is a variation on the well-kenned Rodrigues formula for $SO(3)$, which you can find at the end of my answer here, after one has simplified the expression $\vec{\alpha} \times \left(\vec{\alpha} \times \dot{\vec{\alpha}}\right)$ with standard triple product formulas | |
| Oct 25, 2016 at 20:42 | answer | added | John Alexiou | timeline score: 1 | |
| Oct 25, 2016 at 15:38 | history | edited | Keshav Srinivasan | CC BY-SA 3.0 |
edited title
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| Oct 24, 2016 at 9:55 | answer | added | user130529 | timeline score: 2 | |
| Oct 23, 2016 at 8:29 | history | tweeted | twitter.com/StackPhysics/status/790107949834264577 | ||
| S Oct 23, 2016 at 8:14 | history | bounty started | Keshav Srinivasan | ||
| S Oct 23, 2016 at 8:14 | history | notice added | Keshav Srinivasan | Draw attention | |
| Oct 21, 2016 at 20:44 | comment | added | John Alexiou | Yes, I am translating into a vector-matrix equation. | |
| Oct 21, 2016 at 20:32 | comment | added | Keshav Srinivasan | @ja72 Thanks, I just don't understand what it has to do with my question. Are you trying to translate the vector equation in my question into a matrix equation? | |
| Oct 21, 2016 at 20:27 | comment | added | John Alexiou | Tensors give me headaches. I can understand better things with linear algebra and so I thought there would be others also. Trying to help out. | |
| Oct 21, 2016 at 20:26 | comment | added | Keshav Srinivasan | @ja72 Yeah, I'm aware of that. What's your point? | |
| Oct 21, 2016 at 20:23 | comment | added | John Alexiou | Note that the 3×3 anti-symmetric matrix mentioned is $$[\begin{pmatrix}x\\y\\z\end{pmatrix} \times] = \begin{bmatrix} 0 & -z & y \\ z & 0 & -x \\ -y & x & 0 \end{bmatrix}$$ if you don't want to use the tensor notation for cross products (like in the paper). The above gives $$[\vec{a} \times] \vec{b} \equiv \vec{a} \times \vec{b}$$ | |
| Oct 21, 2016 at 15:20 | comment | added | Keshav Srinivasan | @ja72 Yes, I know that quarternions have advantages over rotation vectors in this regard. But I want to see if we can get a formula for the rotation vector. | |
| Oct 21, 2016 at 15:17 | history | edited | Keshav Srinivasan | CC BY-SA 3.0 |
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| Oct 21, 2016 at 15:15 | comment | added | John Alexiou | There is a reason people use quaternions over rotation vectors. | |
| S Oct 21, 2016 at 6:49 | history | edited | user36790 | CC BY-SA 3.0 |
replaced vec by \vec
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| S Oct 21, 2016 at 6:49 | history | suggested | user130529 | CC BY-SA 3.0 |
replaced vec by \vec
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| Oct 21, 2016 at 6:43 | review | Suggested edits | |||
| S Oct 21, 2016 at 6:49 | |||||
| Oct 21, 2016 at 4:58 | history | edited | user36790 | CC BY-SA 3.0 |
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| Oct 21, 2016 at 4:55 | history | asked | Keshav Srinivasan | CC BY-SA 3.0 |