Timeline for Electric flux through the base of a cube from a point charge infinitesimally close to a vertex?
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 20, 2016 at 17:07 | comment | added | Emilio Pisanty | @knzhou I just don't see much this answer provides over Paul G's given the OP's objections, but in the end it's for the OP to decide. | |
| Oct 20, 2016 at 17:05 | comment | added | knzhou | @EmilioPisanty I did address this! "Since all relevant faces are far away from the charge, it doesn't make any difference if we simply take $\delta = 0$." | |
| Oct 20, 2016 at 17:05 | comment | added | Emilio Pisanty | @knzhou The point is that the OP was presented with this approach and rejected it. As I read it, this is because they were not convinced that the $\delta=0$ calculation of the flux through the $\Phi_2$ faces (which you have performed) also holds for finite $\delta$; at the very least your answer should address this. | |
| Oct 20, 2016 at 16:53 | comment | added | knzhou | @EmilioPisanty I don't think that's what the OP meant. They're just pointing out that the case $\delta = 0$ is different from the case $\delta = \epsilon > 0$ (which you can also see from symmetry arguments). | |
| Oct 20, 2016 at 16:52 | comment | added | Emilio Pisanty | (cf. in particular the OP's comments under Paul G's answer, which is essentially this approach.) | |
| Oct 20, 2016 at 15:02 | comment | added | Emilio Pisanty | My impression from the first round of interaction with the OP was that they are aware of this method, but they wanted an explicit calculation of $\Phi_1$ which they could then add up with $\Phi_2$ to check that the total flux does indeed come to $q/\epsilon_0$ even in the limit. | |
| Oct 19, 2016 at 23:48 | history | answered | knzhou | CC BY-SA 3.0 |