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Sep 17, 2016 at 4:02 review Late answers
Sep 17, 2016 at 4:38
Sep 17, 2016 at 3:50 comment added Sean E. Lake That's not the correct deviation. The potential produced by exchange of massive particles is given by the Yukawa potential: $$U = \frac{k e^2}{r} \operatorname{e}^{-mcr / \hbar}.$$ So the Yukawa force is: $$ F = \frac{ke^2}{r^2} \operatorname{e}^{-mcr/\hbar} \left(\frac{mcr}{\hbar} + 1\right).$$
Sep 17, 2016 at 3:43 history answered JamieBondi CC BY-SA 3.0