Timeline for What will happen if the photon has non-zero mass?
Current License: CC BY-SA 3.0
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Sep 17, 2016 at 4:02 | review | Late answers | |||
Sep 17, 2016 at 4:38 | |||||
Sep 17, 2016 at 3:50 | comment | added | Sean E. Lake | That's not the correct deviation. The potential produced by exchange of massive particles is given by the Yukawa potential: $$U = \frac{k e^2}{r} \operatorname{e}^{-mcr / \hbar}.$$ So the Yukawa force is: $$ F = \frac{ke^2}{r^2} \operatorname{e}^{-mcr/\hbar} \left(\frac{mcr}{\hbar} + 1\right).$$ | |
Sep 17, 2016 at 3:43 | history | answered | JamieBondi | CC BY-SA 3.0 |