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Mar 2, 2011 at 19:14 vote accept John Alexiou
Jan 13, 2011 at 22:44 comment added Marek @jalexiou: sorry, I didn't notice you are not an author of this answer. In that case, I don't know why you think $c = 1$ is not implied :-)
Jan 13, 2011 at 22:42 comment added Marek @jalexiou: then you should make that clear. I thought $c = 1$ is implied ;-)
Jan 13, 2011 at 19:26 comment added John Alexiou The 4-vector above is a block-vector, with 1 time + 3 position quantities. Those do not behave like regular vectors because you cannot get a magnitude out of them without a non-scalar metric (as mentioned elsewhere correctly). In a pure sense a vector has to have the same units, although when it comes to SI prefixes it get complicated like (1 μm,1 km,1 ly) ??
Jan 13, 2011 at 19:00 comment added David Z Although technically you're right about units, in that it is possible to perform well-defined operations on vectors in which the components have different units, it's a major pain in the butt when you're working with linear transformations. It also requires you to introduce a non-identity metric to take the inner product. So in practice usually we normalize the units so that they're the same on all components.
Jan 13, 2011 at 18:54 history edited TROLLHUNTER CC BY-SA 2.5
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Jan 13, 2011 at 18:43 history answered TROLLHUNTER CC BY-SA 2.5