Timeline for Brachistochrone problem for 3 points
Current License: CC BY-SA 3.0
6 events
when toggle format | what | by | license | comment | |
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Aug 2, 2019 at 9:06 | comment | added | Qmechanic♦ | Notes for later: $1+ (\frac{dx}{dy})^2=\frac{k^2}{y}$. Rescale $x$ and $y$ so that $k^2=2$. Then $\frac{dx}{dy}= +(\frac{2}{y}-1)^{-1/2}=\sqrt{\frac{y}{2-y}}$ with antiderivative $x=\arctan \frac{\sqrt{y(2-y)}}{1-y}-\sqrt{y(2-y)}=\theta-\sin\theta$, where $1-y=\cos\theta$. | |
May 6, 2012 at 19:14 | vote | accept | Mathlover | ||
May 6, 2012 at 19:13 | vote | accept | Mathlover | ||
May 6, 2012 at 19:13 | |||||
May 6, 2012 at 6:46 | comment | added | Qmechanic♦ | Here I'm considering the idealized Brachistochrone problem where solution curves are allowed to be only piecewise smooth. Instantaneous change of velocity is provided by an idealized (infinitely big) normal force, which does no work. | |
May 5, 2012 at 22:13 | comment | added | tmac | what about y'? You would still need continuity there, this is not guaranteed with two patched together solutions. | |
May 5, 2012 at 21:37 | history | answered | Qmechanic♦ | CC BY-SA 3.0 |