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Aug 2, 2019 at 9:06 comment added Qmechanic Notes for later: $1+ (\frac{dx}{dy})^2=\frac{k^2}{y}$. Rescale $x$ and $y$ so that $k^2=2$. Then $\frac{dx}{dy}= +(\frac{2}{y}-1)^{-1/2}=\sqrt{\frac{y}{2-y}}$ with antiderivative $x=\arctan \frac{\sqrt{y(2-y)}}{1-y}-\sqrt{y(2-y)}=\theta-\sin\theta$, where $1-y=\cos\theta$.
May 6, 2012 at 19:14 vote accept Mathlover
May 6, 2012 at 19:13 vote accept Mathlover
May 6, 2012 at 19:13
May 6, 2012 at 6:46 comment added Qmechanic Here I'm considering the idealized Brachistochrone problem where solution curves are allowed to be only piecewise smooth. Instantaneous change of velocity is provided by an idealized (infinitely big) normal force, which does no work.
May 5, 2012 at 22:13 comment added tmac what about y'? You would still need continuity there, this is not guaranteed with two patched together solutions.
May 5, 2012 at 21:37 history answered Qmechanic CC BY-SA 3.0