Timeline for Neutron-Antineutron Annihilation
Current License: CC BY-SA 3.0
9 events
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Sep 1, 2016 at 15:34 | comment | added | HolgerFiedler | @dmckee To conclude from charged particles with their opposite electric fields to neutrons is a strange thought. What in the experiments with antineutrons happens when the hit an obstacle or came in contact with gas molecules? Are they annihilate with the nucleuses neutrons? Any experimental evidence? | |
Sep 1, 2016 at 2:12 | comment | added | dmckee --- ex-moderator kitten | Positronium annihilation happens at $\mathrm{eV}$ relative energies and on average at relative rest; the formation of the 'atomic' state is accompanied by radiating off the relative kinetic energy. Nor does "pure energy" mean anything; many annihilation ends in photon states, but those are only characterized as "pure energy" in pop-sci and science fiction. | |
Aug 31, 2016 at 23:14 | comment | added | rob♦ | @HolgerFiedler I'll turn your challenge around: you survey the literature and figure out what the energies involved are and where the data are missing. I don't know to what extent antineutrons thermalize before annihilating, so you can't just consider beam energy. | |
Aug 31, 2016 at 20:28 | comment | added | HolgerFiedler | @dmckee Please give sources for change of particle interactions from not fast moving (MeV) particles and pure energy at the next moment. | |
Aug 31, 2016 at 20:16 | comment | added | HolgerFiedler | @rob Any source for experimental data on no relativistic velocity? | |
Aug 31, 2016 at 20:04 | review | Low quality answers | |||
Aug 31, 2016 at 20:14 | |||||
Aug 31, 2016 at 19:53 | comment | added | rob♦ | Your prediction that neutron-antineutron annihilation cannot occur is wrong. The relevant literature is easy to find. | |
Aug 31, 2016 at 19:52 | comment | added | dmckee --- ex-moderator kitten | "Usually it means the attraction of charged particles from different sign" No. It doesn't. Sure, most of the usual example involve charged particles but that fact has absolutely nothing to do with the notion of annihilation which does involve the destruction of a pair of states having opposite counted quantum numbers (lepton, baryon, weak-hyperchage, electric charge and so on). Neutrons may have electric charge zero, but they carry baryon number. | |
Aug 31, 2016 at 19:27 | history | answered | HolgerFiedler | CC BY-SA 3.0 |