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May 3, 2021 at 0:41 answer added doetoe timeline score: 2
Aug 7, 2016 at 13:10 history tweeted twitter.com/StackPhysics/status/762274789851598848
Aug 6, 2016 at 21:54 comment added user12029 Lorentz transformations in special relativity is not about conservation of some "$x^2-t^2$" form, with x and t being coordinates. They're about conserving the metric at every point in spacetime. The former is not really geometric, while the latter is.
Aug 6, 2016 at 18:36 history reopened peterh
rob
Brandon Enright
Qmechanic
Aug 6, 2016 at 18:36 history rollback Qmechanic
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Aug 6, 2016 at 15:21 history edited Ben Selfridge CC BY-SA 3.0
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Aug 6, 2016 at 13:19 comment added udrv @BenSelfridge In intuitive terms, beyond preserving the interval: A physically acceptable transformation is expected to transform any linear uniform motion into a linear uniform motion. Your transformation maps every linear uniform motion that passes through the origin into a similar one, but does not do so for arbitrary linear motions that do not intercept the origin. Interesting example anyway.
Aug 6, 2016 at 6:47 review Reopen votes
Aug 6, 2016 at 18:36
Aug 6, 2016 at 6:30 history edited Qmechanic CC BY-SA 3.0
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Aug 6, 2016 at 6:25 history closed auden
CuriousOne
John Rennie special-relativity
Duplicate of Interval preserving transformations are linear in special relativity
S Aug 6, 2016 at 2:18 history suggested CommunityBot CC BY-SA 3.0
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Aug 5, 2016 at 23:03 history protected Qmechanic
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Aug 5, 2016 at 19:13 answer added knzhou timeline score: 12
Aug 5, 2016 at 19:12 history edited Qmechanic
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S Aug 5, 2016 at 19:09 history suggested Mass CC BY-SA 3.0
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Aug 5, 2016 at 19:02 history asked Ben Selfridge CC BY-SA 3.0