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Mar 23, 2021 at 21:57 comment added endolith Water and air don't even use the same reference level. 0 dBSPL in air is 20 μPa. 0 dBSPL underwater is 1 μPa.
Jun 11, 2020 at 9:33 history edited CommunityBot
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Oct 5, 2016 at 0:40 vote accept uhoh
Oct 4, 2016 at 14:18 history edited user36790 CC BY-SA 3.0
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Oct 4, 2016 at 14:16 answer added honeste_vivere timeline score: 10
Aug 5, 2016 at 4:03 history tweeted twitter.com/StackPhysics/status/761412195758538752
Aug 5, 2016 at 3:02 history edited uhoh CC BY-SA 3.0
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Aug 5, 2016 at 3:00 comment added CuriousOne OK... so remove 61dB, then, but that still leaves you short of a factor of 1000, or so.
Aug 5, 2016 at 2:59 history edited uhoh CC BY-SA 3.0
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Aug 5, 2016 at 2:51 comment added uhoh @CuriousOne this is acoustic power, not loudness. 10 is correct here. However that means that the 61dB should be 30.5dB which looks like the ratio of the densities., My question is, do I need to apply that "water to air" correction to my power (and energy) estimate, or is that only for loudness considerations?
Aug 5, 2016 at 2:50 comment added CuriousOne Loudness is usually specified in $dB_{Amplitude}$, so that's twice the number of $dB_{Intensity}$.
Aug 5, 2016 at 2:47 history edited uhoh CC BY-SA 3.0
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Aug 5, 2016 at 2:46 comment added uhoh @ChrisWhite - Ah, I assumed 1 square meter but didn't mention it - I'll fix that. Thanks!
Aug 5, 2016 at 2:38 history edited uhoh CC BY-SA 3.0
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Aug 5, 2016 at 2:38 comment added CuriousOne You are using 230dB on the power formula, when it's really meant to be used with the amplitude formula, i.e. 20dB is a change of a factor of 10, not 10dB. That should put things into the right order of magnitude. :-)
Aug 5, 2016 at 2:36 history asked uhoh CC BY-SA 3.0