Timeline for Potential of cells in series
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Aug 2, 2016 at 11:18 | comment | added | garyp | That charge that went through only the 5 V cell started at a potential of 10 V. So its final potential is 15 V. (I'm assuming here that 0 V is at the far left of your diagram, and the polarity of the cells is positive to the right. Conventionally, the longer line is the positive side of the cell.) Am I not understanding the question? | |
| Aug 2, 2016 at 5:34 | answer | added | Dawood ibn Kareem | timeline score: 2 | |
| Aug 2, 2016 at 5:28 | history | edited | Sharpfawkes | CC BY-SA 3.0 |
deleted 2 characters in body
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| S Aug 2, 2016 at 5:27 | history | suggested | Dawood ibn Kareem | CC BY-SA 3.0 |
added picture
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| Aug 2, 2016 at 5:27 | comment | added | Sharpfawkes | Yeah, sorry. My mistake. I'll edit the question. | |
| Aug 2, 2016 at 4:40 | review | Suggested edits | |||
| S Aug 2, 2016 at 5:27 | |||||
| Aug 2, 2016 at 4:28 | history | edited | Qmechanic♦ | CC BY-SA 3.0 |
deleted 7 characters in body; edited tags
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| Aug 2, 2016 at 3:41 | history | asked | Sharpfawkes | CC BY-SA 3.0 |