Skip to main content
Physics

Return to Question

edited tags
Source Link
Qmechanic ♦
Qmechanic ♦
  • 213.1k
  • 48
  • 590
  • 2.3k

Is there any physical interpretation of nashNash embedding theorem?

Nash embedding theorem says that every Riemannian manifold can be (isometrically) embedded into $R^n$. That means that every $RM$ is a sub-manifold to $R^n$.

Since General Relativity is defined on a pseudo-Riemannian manifold and classical theories are defined on a "simple" euclideanEuclidean space, I want to ask what the embedding theorem means for the relation between GR and classical physics.

Is there any physical interpretation of nash embedding theorem?

Nash embedding theorem says that every Riemannian manifold can be (isometrically) embedded into $R^n$. That means that every $RM$ is a sub-manifold to $R^n$.

Since General Relativity is defined on a pseudo-Riemannian manifold and classical theories are defined on a "simple" euclidean space, I want to ask what the embedding theorem means for the relation between GR and classical physics.

Is there any physical interpretation of Nash embedding theorem?

Nash embedding theorem says that every Riemannian manifold can be (isometrically) embedded into $R^n$. That means that every $RM$ is a sub-manifold to $R^n$.

Since General Relativity is defined on a pseudo-Riemannian manifold and classical theories are defined on a "simple" Euclidean space, I want to ask what the embedding theorem means for the relation between GR and classical physics.

added 7 characters in body; edited title
Source Link
auden
auden
  • 7.1k
  • 4
  • 33
  • 60

Is there any physical interpretation of Nashnash embedding theorem?

Nash embedding theorem says that every Riemannian manifold can be (isometrically) embedded into R^n$R^n$. That means that every RM$RM$ is a submanifoldsub-manifold to R^n$R^n$.

Since General Relativity is defined on a pseudo-riemannianRiemannian manifold and classical theories are defined on a "simple" euclidianeuclidean space, I want to ask what the embedding theorem means for the relation between GR and classical physics.

Is there any physical interpretation of Nash embedding theorem?

Nash embedding theorem says that every Riemannian manifold can be (isometrically) embedded into R^n. That means that every RM is a submanifold to R^n.

Since General Relativity is defined on a pseudo-riemannian manifold and classical theories are defined on a "simple" euclidian space, I want to ask what the embedding theorem means for the relation between GR and classical physics.

Is there any physical interpretation of nash embedding theorem?

Nash embedding theorem says that every Riemannian manifold can be (isometrically) embedded into $R^n$. That means that every $RM$ is a sub-manifold to $R^n$.

Since General Relativity is defined on a pseudo-Riemannian manifold and classical theories are defined on a "simple" euclidean space, I want to ask what the embedding theorem means for the relation between GR and classical physics.

edited tags
Link
Qmechanic ♦
Qmechanic ♦
  • 213.1k
  • 48
  • 590
  • 2.3k

Is there any physical interpretation of nashNash embedding theorem?

Source Link
Physics Guy
Physics Guy
  • 94
  • 8