Timeline for Does entropy measure extractable work?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 29, 2011 at 7:20 | comment | added | Marco | More recent results here arxiv.org/abs/0908.0424 and here arxiv.org/abs/1009.1630 | |
| Sep 16, 2011 at 15:28 | vote | accept | Javier Rodriguez Laguna | ||
| Sep 16, 2011 at 14:30 | comment | added | Joe Fitzsimons | @Javier: Yes, you can use exactly the same trick, but use a measurement that returns 0 if the particle is in the left most compartment, and 1 with probability $p$ if the particle is in the rightmost compartment and 0 otherwise, and proceed from there. Have a look at the paper, there's lots of good stuff in it. | |
| Sep 16, 2011 at 14:14 | comment | added | Javier Rodriguez Laguna | Yes, I see. But still with the Szilard engine example, I'd like to go further. If I know in which side the particle si, I can extract kT ln(2) of work. If I don't know where the particle is, I can get no work. But, what if I have partial knowledge? Is still Shannon's entropy the answer? | |
| Sep 16, 2011 at 13:41 | history | answered | Joe Fitzsimons | CC BY-SA 3.0 |