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The charged accelerometer will register a non vanishing acceleration. The reason why the setup you are proposing (interaction via electric charge) gives a physically distinct result from the setup in the answer you linked (interaction via gravity), even though they can be described by the same mathematical force, is because the Equivalence Principle applies for the latter but not for the former.

The Equivalence Principle requires that inertial (the mass $m_i$ in Newton's second law) and gravitational masses (the mass $m_g$ in the Universal Gravitation law) equal each other. Then all free falling bodies will have the same acceleration, namely $$m_ia=m_g g\Rightarrow a=g.$$

On the other hand the same does not happen for a charged particle "falling freely" under action of an electric field $E$ (let us neglect gravity). The acceleration of the body depends on its electric charge $q$ as well as on its inertial mass, $$m_ia=qE\Rightarrow a=\frac{qE}{m_i}.$$ Now imagine your accelerometer consists of an electrically charged bob in the center of an electrically neutral box. When the system is put in orbit (or in "free fall") around a fixed charge, then the bob will move with respect to the box and this will give the acceleration reading.

The charged accelerometer will register a non vanishing acceleration. The reason why the setup you are proposing (interaction via electric charge) gives a physically distinct result from the setup in the answer you linked (interaction via gravity), even though they can be described by the same mathematical force, is because the Equivalence Principle applies for the latter but not for the former.

The Equivalence Principle requires that inertial (the mass $m_i$ in Newton's second law) and gravitational masses (the mass $m_g$ in the Universal Gravitation law) equal each other. Then all free falling bodies will have the same acceleration, namely $$m_ia=m_g g\Rightarrow a=g.$$

On the other hand the same does not happen for a charged particle "falling freely" under action of an electric field $E$ (let us neglect gravity). The acceleration of the body depends on its electric charge $q$ as well as on its inertial mass, $$m_ia=qE\Rightarrow a=\frac{qE}{m_i}.$$ Now imagine your accelerometer consists of an electrically charged bob in the center of an electrically neutral box. When the system is put in orbit (or in "free fall") around a fixed charge, then the bob will move with respect to the box and this will give the acceleration reading.

The charged accelerometer will register a non vanishing acceleration. The reason why the setup you are proposing (interaction via electric charge) gives a physically distinct result from the setup in the answer you linked (interaction via gravity), even though they can be described by the same mathematical force, is because the Equivalence Principle holds for the latter but not for the former.

The Equivalence Principle requires that inertial (the mass $m_i$ in Newton's second law) and gravitational masses (the mass $m_g$ in the Universal Gravitation law) equal each other. Then all free falling bodies will have the same acceleration, namely $$m_ia=m_g g\Rightarrow a=g.$$

On the other hand the same does not happen for a charged particle "falling freely" under action of an electric field $E$ (let us neglect gravity). The acceleration of the body depends on its electric charge $q$ as well as on its inertial mass, $$m_ia=qE\Rightarrow a=\frac{qE}{m_i}.$$ Now imagine your accelerometer consists of an electrically charged bob in the center of an electrically neutral box. When the system is put in orbit (or in "free fall") around a fixed charge, then the bob will move with respect to the box and this will give the acceleration reading.

The charged accelerometer will register a non vanishing acceleration. The reason why the setup you are proposing (interaction via electric charge) gives a physically distinct result from the setup in the answer you linked (interaction via gravity), even though they can be described by the same mathematical force, is because the Equivalence Principle applies for the latter but not for the former.

The Equivalence Principle requires that inertial (the mass $m_i$ in Newton's second law) and gravitational masses (the mass $m_g$ in the Universal Gravitation law) equal each other. Then all free falling bodies will have the same acceleration, namely $$m_ia=m_g g\Rightarrow a=g.$$

On the other hand the same does not happen for a charged particle "falling freely" under action of an electric field $E$ (let us neglect gravity). The acceleration of the body depends on its electric charge $q$ as well as on its inertial mass, $$m_ia=qE\Rightarrow a=\frac{qE}{m_i}.$$ Now imagine your accelerometer consists of an electrically charged bob in the center of an electrically neutral box. When the system is put in orbit (or in "free fall") around a fixed charge, then the bob will move with respect to the box and this will give the acceleration reading.

The charged accelerometer will register a non vanishing acceleration. The reason why the setup you are proposing (interaction via electric charge) gives a physically distinct result from the setup in the answer you linked (interaction via gravity), even though they can be described by the same mathematical force, is because the Equivalence Principle holds for the latter but not for the former.

The Equivalence Principle requires that inertial (the mass $m_i$ in Newton's second law) and gravitational masses (the mass $m_g$ in the Universal Gravitation law) equal each other. Then all free falling bodies will have the same acceleration, namely $$m_ia=m_g g\Rightarrow a=g.$$

On the other hand the same does not happen for a charged particle "falling freely" under action of an electric field $E$ (let us neglect gravity). The acceleration of the body depends on its electric charge $q$ as well as on its inertial mass, $$m_ia=qE\Rightarrow a=\frac{qE}{m_i}.$$ Now imagine your accelerometer consists of an electric charged bob in the center of an electric neutral box. When the system is put in orbit (or in "free fall") around a fixed charge, then the bob will move with respect to the box and this will give the acceleration reading.

The charged accelerometer will register a non vanishing acceleration. The reason why the setup you are proposing (interaction via electric charge) gives a physically distinct result from the setup in the answer you linked (interaction via gravity), even though they can be described by the same mathematical force, is because the Equivalence Principle holds for the latter but not for the former.

The Equivalence Principle requires that inertial (the mass $m_i$ in Newton's second law) and gravitational masses (the mass $m_g$ in the Universal Gravitation law) equal each other. Then all free falling bodies will have the same acceleration, namely $$m_ia=m_g g\Rightarrow a=g.$$

On the other hand the same does not happen for a charged particle "falling freely" under action of an electric field $E$ (let us neglect gravity). The acceleration of the body depends on its electric charge $q$ as well as on its inertial mass, $$m_ia=qE\Rightarrow a=\frac{qE}{m_i}.$$ Now imagine your accelerometer consists of an electrically charged bob in the center of an electrically neutral box. When the system is put in orbit (or in "free fall") around a fixed charge, then the bob will move with respect to the box and this will give the acceleration reading.