Timeline for Charged Accelerometer in Orbit
Current License: CC BY-SA 3.0
15 events
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| Jul 17, 2016 at 2:42 | history | edited | Selene Routley | CC BY-SA 3.0 |
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| Jul 17, 2016 at 2:42 | comment | added | Selene Routley | @ChrisWhite Yes, thanks heaps, I missed that part about the orbitted object 'sbeing small. You're exactly right- the path in both case would be the exactly the same but the two spacetime metrics are different, so the path is only a geodesic in A. It sounds as though the OP has gleaned useful insight notwithstanding my clumsiness. | |
| Jul 17, 2016 at 2:36 | comment | added | user10851 | Regarding your second and third sentences, I think the OP was asking about a massless but charged primary body affecting a test accelerometer. That is, there is case A -- massive primary and accelerometer held in orbit by gravity -- and case B -- charged, massless primary and accelerometer held in orbit by Coulomb. Just because the path in A and B looks the same, it's only a spacetime geodesic in case A. | |
| Jul 17, 2016 at 2:35 | comment | added | Selene Routley | @SamuelLi ..... "Star Wars" phase she showed me specifications for Emperor Palpatine's personal ship and asked how it could accelerate at 1600 g without the evil emperor turning into a bucket of mashed body parts. At that point, we together "designed" an electrostatic drive exactly like your accelerometer when uniformly charged. Palpatine could accelerate arbitrarily swiftly if he were uniformly charged and undergo no strain in his body. PS: If you want your comment back to put in your own answer, I'll delete it from mine, but I wanted it preserved (comments can get deleted). | |
| Jul 17, 2016 at 2:33 | comment | added | Selene Routley | @SamuelLi Exactly. I've taken the liberty of putting your comment as a footnote to my answer, because it is a beautifully written summary of what I am trying to say. Incidentally, I recalled last night after answering this question, another answer of mine here. Take a look at the last paragraph. A body force that accelerates all points of a body equally (as an electrostatic field on a uniformly charged body causes the body to undergo an isometry and there is no strain anywhere in the body. When my daughter was going through her .... | |
| Jul 17, 2016 at 2:29 | history | edited | Selene Routley | CC BY-SA 3.0 |
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| Jul 17, 2016 at 1:25 | comment | added | Samuel Li | Just a small insight I gleaned from your answer - if the accelerometer uses some kind of physical (e.g. mass-and-spring) system to measure acceleration, then once it is charged it is no longer an accelerometer. Other influences beside its acceleration now affect the accelerometer reading. | |
| Jul 17, 2016 at 1:22 | comment | added | T.C. Proctor | By your definition, no accelerometer is "working as a true accelerometer", as every accelerometer has gravitational mass. A "true accelerometer" would have inertial mass but no gravitational mass, and thus read a non-zero acceleration in gravitational orbit. I think the OP's question came down to "if I replace the gravitational force by an analogous electromagnetic force, will it have the same property?" | |
| Jul 16, 2016 at 23:44 | comment | added | Selene Routley | @JanDvorak Yes, of course! We'll going into business building laser accelerometers as rivals companies, and your company is going to slay mine wholesale! | |
| Jul 16, 2016 at 19:04 | comment | added | John Dvorak | "If, however, the accelerometer were a laser based system inferring acceleration through deviation of light paths," - wouldn't it be easier to measure the Doppler shift? | |
| Jul 16, 2016 at 18:15 | vote | accept | Samuel Li | ||
| Jul 16, 2016 at 16:03 | history | edited | Selene Routley | CC BY-SA 3.0 |
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| Jul 16, 2016 at 15:45 | history | edited | Selene Routley | CC BY-SA 3.0 |
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| Jul 16, 2016 at 15:35 | history | edited | Selene Routley | CC BY-SA 3.0 |
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| Jul 16, 2016 at 15:30 | history | answered | Selene Routley | CC BY-SA 3.0 |