Timeline for A function for calculating velocity at several distances as you fall towards the earth's center
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
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| Jul 8, 2016 at 2:12 | comment | added | Floris | @readytolearn - yes it can. I have updated my answer accordingly. | |
| Jul 8, 2016 at 2:11 | history | edited | Floris | CC BY-SA 3.0 |
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| Jul 7, 2016 at 22:08 | comment | added | readytolearn | Can that be incorporated into a calculus/differential velocity function? that adds the summations since the decrease in acceleration at each point. | |
| Jul 7, 2016 at 21:28 | comment | added | Floris | @readytolearn - force is acceleration times mass... | |
| Jul 7, 2016 at 21:28 | comment | added | Floris | @PaulT. - you are right. I wrote "acceleration" but used 'g'. Fixed. | |
| Jul 7, 2016 at 21:27 | comment | added | readytolearn | I thought gravitational force and acceleration due to gravity is equal. since N/kg = (kgm)/kgs^2 = m/s^2 | |
| Jul 7, 2016 at 21:27 | history | edited | Floris | CC BY-SA 3.0 |
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| Jul 7, 2016 at 21:25 | comment | added | Paul T. | I think there is a small typo: I believe the equation given is the acceleration, not force. | |
| Jul 7, 2016 at 21:24 | history | edited | Floris | CC BY-SA 3.0 |
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| Jul 7, 2016 at 21:23 | comment | added | Floris | Sorry - yes. I will add... | |
| Jul 7, 2016 at 21:22 | comment | added | readytolearn | Where G is the gravitational constant and R is distance from earth’s center ? | |
| Jul 7, 2016 at 21:11 | history | answered | Floris | CC BY-SA 3.0 |