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Can we derive Biot Savart law from coulomb'sCoulomb's law by setting a current source at an instant in place of one of the charges. Lets? Let's say $dl$ is the length of the conductor having $dQ$ charge which applies some force at the other charge at some instant of time. Taking derivates on both sides we get some Currentcurrent term. But how to prove it??

By Coulomb's law

$dE = k*dq/r^2$$dE = k \frac{dq}{r^2}$

$\dfrac{dE}{dt} = k.\dfrac{I}{r^2}$$\dfrac{dE}{dt} = k\dfrac{I}{r^2}$

$dl\times \dfrac{dE}{dt} = k*I*dl \times \dfrac{ r}{r^3}$ (in vector form)$d\vec{l}\times \dfrac{d\vec{E}}{dt} = k I d\vec{l} \times \dfrac{ \vec{r}}{r^3}$

Is it correct? If yes, how toshould I proceed ahead.?

Can we derive Biot Savart law from coulomb's by setting a current source at an instant in place of one of the charges. Lets say $dl$ length of the conductor having $dQ$ charge which applies some force at the other charge at some instant of time. Taking derivates on both sides we get some Current term. But how to prove it??

By Coulomb's law

$dE = k*dq/r^2$

$\dfrac{dE}{dt} = k.\dfrac{I}{r^2}$

$dl\times \dfrac{dE}{dt} = k*I*dl \times \dfrac{ r}{r^3}$ (in vector form)

Is it correct? If yes, how to proceed ahead.

Can we derive Biot Savart law from Coulomb's law by setting a current source at an instant in place of one of the charges? Let's say $dl$ is the length of the conductor having $dQ$ charge which applies some force at the other charge at some instant of time. Taking derivates on both sides we get some current term. But how to prove it?

By Coulomb's law

$dE = k \frac{dq}{r^2}$

$\dfrac{dE}{dt} = k\dfrac{I}{r^2}$

$d\vec{l}\times \dfrac{d\vec{E}}{dt} = k I d\vec{l} \times \dfrac{ \vec{r}}{r^3}$

Is it correct? If yes, how should I proceed ahead?

Can we derive Biot Savart law from coulomb's by setting a current source at an instant in place of one of the charges. Lets say dl$dl$ length of the conductor having dQ$dQ$ charge which applies some force at the other charge at some instant of time. Taking derivates on both sides we get some Current term. But how to prove it??

By Coulomb's law

dE = k*dq/r^2$dE = k*dq/r^2$

dE/dt = k*I/r^2$\dfrac{dE}{dt} = k.\dfrac{I}{r^2}$

dl X dE/dt = kIdl X r/r^3$dl\times \dfrac{dE}{dt} = k*I*dl \times \dfrac{ r}{r^3}$ (in vector form)

Is it correct? If yes, how to proceed ahead.

Can we derive Biot Savart law from coulomb's by setting a current source at an instant in place of one of the charges. Lets say dl length of the conductor having dQ charge which applies some force at the other charge at some instant of time. Taking derivates on both sides we get some Current term. But how to prove it??

By Coulomb's law

dE = k*dq/r^2

dE/dt = k*I/r^2

dl X dE/dt = kIdl X r/r^3 (in vector form)

Is it correct? If yes, how to proceed ahead.

Can we derive Biot Savart law from coulomb's by setting a current source at an instant in place of one of the charges. Lets say $dl$ length of the conductor having $dQ$ charge which applies some force at the other charge at some instant of time. Taking derivates on both sides we get some Current term. But how to prove it??

By Coulomb's law

$dE = k*dq/r^2$

$\dfrac{dE}{dt} = k.\dfrac{I}{r^2}$

$dl\times \dfrac{dE}{dt} = k*I*dl \times \dfrac{ r}{r^3}$ (in vector form)

Is it correct? If yes, how to proceed ahead.

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Can we derive Biot Savart law from Coulomb's law?

Can we derive Biot Savart law from coulomb's by setting a current source at an instant in place of one of the charges. Lets say dl length of the conductor having dQ charge which applies some force at the other charge at some instant of time. Taking derivates on both sides we get some Current term. But how to prove it??

By Coulomb's law

dE = k*dq/r^2

dE/dt = k*I/r^2

dl X dE/dt = kIdl X r/r^3 (in vector form)

Is it correct? If yes, how to proceed ahead.