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Post Closed as "Duplicate" by ACuriousMind♦, user36790, John Rennie special-relativity
Question Protected by Qmechanic♦
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Qmechanic ♦
Qmechanic ♦
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Why must v$v$ be < c$< c$ in the lorentzLorentz transformations? Do these equations not apply to light?

I was trying to understand how things look from the perspective of light. Looking at the Lorentz transformations, it seems that the universe would contract along the direction of movement into a plane, and time would stop. But I have heard that these equations cannot be applied to light speed, when v=c$v=c$.

Why don't the lorentzLorentz transformations apply when v=c$v=c$?

Why must v be < c in the lorentz transformations? Do these equations not apply to light?

I was trying to understand how things look from the perspective of light. Looking at the Lorentz transformations, it seems that the universe would contract along the direction of movement into a plane, and time would stop. But I have heard that these equations cannot be applied to light speed, when v=c.

Why don't the lorentz transformations apply when v=c?

Why must $v$ be $< c$ in the Lorentz transformations? Do these equations not apply to light?

I was trying to understand how things look from the perspective of light. Looking at the Lorentz transformations, it seems that the universe would contract along the direction of movement into a plane, and time would stop. But I have heard that these equations cannot be applied to light speed, when $v=c$.

Why don't the Lorentz transformations apply when $v=c$?

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Luke
Luke
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Why must v be < c in the lorentz transformations? Do these equations not apply to light?

I was trying to understand how things look from the perspective of light. Looking at the Lorentz transformations, it seems that the universe would contract along the direction of movement into a plane, and time would stop. But I have heard that these equations cannot be applied to light speed, when v=c.

Why don't the lorentz transformations apply when v=c?