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Jun 19, 2016 at 15:07 comment added auxsvr @DavidC. Also, I know that many physicists (me included) abuse notation and write $E(P)$, when in fact they mean "a function that takes values of pressure and returns energy", but in mathematical terms $E(P)$ means $E(V)$ if you replace $V\mapsto P$, which doesn't make sense and may confuse you.
Jun 19, 2016 at 15:03 comment added auxsvr @DavidC. Yes, but there is the problem that $E(V,S)$ is convex in a small interval and may not be what you need.
Jun 19, 2016 at 14:47 comment added DavidC. Does that mean that $E(P)$ is simply $E(P) = PV + E_{0}+\frac{9V_{0}B_{0}}{16}\left \{ \left [ \left ( \frac{V_{0}}{V} \right )^\frac{2}{3} -1 \right ]^3 B_{0}^{'}+\left [ \left ( \frac{V_{0}}{V} \right )^{\frac{2}{3}}-1 \right ]^{2}\left [ 6-4\left (\frac{V_0}{V} \right )^{\frac{2}{3}} \right ]\right \}$ ?
Jun 19, 2016 at 11:26 history answered auxsvr CC BY-SA 3.0