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Jun 8, 2016 at 10:07 history closed CuriousOne
user36790
ACuriousMind
honeste_vivere
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Needs details or clarity
Jun 7, 2016 at 9:27 answer added user56903 timeline score: 2
Jun 7, 2016 at 8:37 history edited Qmechanic
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Jun 4, 2016 at 13:30 answer added Lawrence B. Crowell timeline score: 3
Jun 4, 2016 at 8:43 vote accept huseyin tugrul buyukisik
Jun 4, 2016 at 7:00 answer added John Rennie timeline score: 3
Jun 4, 2016 at 2:47 review Close votes
Jun 8, 2016 at 10:07
Jun 4, 2016 at 2:37 comment added CuriousOne The energy loss due to friction is of almost no importance to a rocket, it compromises only about 5% of the total energy needed for the launch. What is of importance is the aerodynamic stress on the rocket, but Max Q (max. aerodynamic pressure) occurs at an altitude of approx. 10-15km (around 90s after liftoff) and is usually countered with a slight throttling of the engines. If there was a reason to reduce it significantly, we would be launching from high elevation sites (4000m+ in altitude), but technically it's really more of an inconvenience than a real problem.
Jun 4, 2016 at 1:04 comment added fibonatic Wouldn't the static electric repulsion also exert an opposing force on the rocket and just be a substitution for the drag. Also ionizing air will make molecules split up in both positive and negative changed particles. So the rocket can't repel both.
Jun 4, 2016 at 0:32 comment added dmckee --- ex-moderator kitten Hm. It's not everyday that Stack Exchange imitates SMBC.
Jun 4, 2016 at 0:03 history edited huseyin tugrul buyukisik CC BY-SA 3.0
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Jun 3, 2016 at 23:55 history edited huseyin tugrul buyukisik CC BY-SA 3.0
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Jun 3, 2016 at 23:49 history edited huseyin tugrul buyukisik CC BY-SA 3.0
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Jun 3, 2016 at 23:44 history edited huseyin tugrul buyukisik CC BY-SA 3.0
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Jun 3, 2016 at 23:38 history asked huseyin tugrul buyukisik CC BY-SA 3.0