Timeline for Sech laser pulse time-bandwidth product calculation

5 events

when toggle format	what		by	license	comment
May 11, 2016 at 8:45	vote	accept	Merin
May 10, 2016 at 15:03	history	edited	Gucio	CC BY-SA 3.0	added 325 characters in body
May 10, 2016 at 14:59	comment	added	Gucio		@Merin No, i meant $\frac{1}{\sqrt{2\alpha}} x$ so that when I solve for $\omega_0$ if I plug in $x^2=y=0.5$ I get the $\omega_0$ value where the squared gaussian is at half of its maximum ($\frac{1}{\sqrt{2\alpha}} $.
May 10, 2016 at 14:01	comment	added	Merin		Do you mean $\frac{1}{\sqrt{2 \alpha}} e^{-\omega_0^2 / 4 \alpha} = \frac{1}{\sqrt{2 \alpha}} \frac{1}{x}$? Also could you show what your expressions for $\Delta t$ and $\Delta \omega$ of the $\operatorname{sech}$ pulse looked like? Do you use $\operatorname{sech} = \frac{2}{e^{\alpha x} + e^{-\alpha x}}$ in the calculation? I am not getting 0.315.
May 10, 2016 at 12:50	history	answered	Gucio	CC BY-SA 3.0