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Timeline for Bernoullis in Parallel pipes

Current License: CC BY-SA 3.0

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May 16, 2016 at 3:47 vote accept Tom Chester
May 11, 2016 at 11:18 answer added Chet Miller timeline score: 0
May 11, 2016 at 3:36 comment added Tom Chester @chestermiller you'll note ive done this for inviscid flow only'. as I said if we were to add head loss my thinking is that the situation would be further apart not closer. I should add that I am also aware of streamwise gradients from the confluence to the exit. Favourable for the slow flow 109.37-100 and Unfavourable for the fast 62.5-100 is that the only mechanism(with viscosity) to bring the adjacent streamlines back together ? or is there something else that prevents them from developing different Bernoulli conditions ?
May 11, 2016 at 3:12 comment added Tom Chester Hi @chestermiller I have added in the breakdown
May 11, 2016 at 3:08 history edited Tom Chester CC BY-SA 3.0
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May 11, 2016 at 3:05 comment added Tom Chester Bernoullis Start - assume a flow velocity 5ms static pressure SP 100 $Q_s=A1.V1$ $Q_s=3.5$ $Q_s=15$ $TP=SP+\frac{1}2mv^2$ $TP=100+\frac{1}25^2$ $TP=112.5$ Stream a $QA=A1.V1=A2.V2$ $A1.V1 =A2.V2$ $2A.5ms = 1A.10ms$ $112.5=SP+\frac{1}2m10^2$ $SP=112.5-50$ $SP=62.5 **Stream b** $A1.V1 =A2.V2$ $1A.5ms^-1 = 2A.2.5ms^-1$ $112.5.5=SP+DP$ $SP=112.5-\frac{1}2m2.5^2$ $SP=112.5-3.125$ $SP=109.375 **Q Check** $Q_s=3.5$=15=1.5+2.5=QA+QB=1.2.5+1.10=3.5=Q_e$
May 10, 2016 at 15:29 comment added Chet Miller Let's see your two Bernoulli equations for the two parallel ducts.
May 10, 2016 at 12:13 comment added Tom Chester Hi @ChesterMiller Yes it is most like square ducting so area would probably be more appropriate
May 10, 2016 at 10:49 comment added Chet Miller Did you mean diameters, or did you mean areas?
May 10, 2016 at 4:06 review First posts
May 10, 2016 at 6:16
May 10, 2016 at 4:04 history asked Tom Chester CC BY-SA 3.0