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ELECTRIC POTENTIAL AND WORK Electric potential and work

a unit positive charge q is placed in an electric field caused due to a positive charge Q. q experiences force of repulsion (FR). we apply an external force (FEXT) opposite TO FR. the test charge moves in the direction opposite to electric field. work is done OPPOSITE TO the field. this work done is stored as potential difference.

A unit positive charge $q$ is placed in an electric field caused due to a positive charge $Q$. $q$ experiences force of repulsion $F_R$. We apply an external force (FEXT) opposite to $F_R$. The test charge moves in the direction opposite to electric field. Work is done opposite to the field. This work done is stored as potential difference.

nowNow my doubt is below:-

weWe know that FR=-FEXT so$F_R=-F_\mathrm{ext}$, so two equal and opposite forces are acting on the charge q$q$. itIf they are equal and opposite, they should cancel out each other know? thenWhen how is work done against the field.? whyWhy is the charge q$q$ moving in the direction of external force if the repulsive force  (equal in magnitude) is opposing it?

ELECTRIC POTENTIAL AND WORK

a unit positive charge q is placed in an electric field caused due to a positive charge Q. q experiences force of repulsion (FR). we apply an external force (FEXT) opposite TO FR. the test charge moves in the direction opposite to electric field. work is done OPPOSITE TO the field. this work done is stored as potential difference.

now my doubt is below:-

we know that FR=-FEXT so two equal and opposite forces are acting on the charge q. it they are equal and opposite, they should cancel out each other know? then how is work done against the field.? why is the charge q moving in the direction of external force if the repulsive force(equal in magnitude) is opposing it?

Electric potential and work

A unit positive charge $q$ is placed in an electric field caused due to a positive charge $Q$. $q$ experiences force of repulsion $F_R$. We apply an external force (FEXT) opposite to $F_R$. The test charge moves in the direction opposite to electric field. Work is done opposite to the field. This work done is stored as potential difference.

Now my doubt is below:

We know that $F_R=-F_\mathrm{ext}$, so two equal and opposite forces are acting on the charge $q$. If they are equal and opposite, they should cancel out each other know? When how is work done against the field? Why is the charge $q$ moving in the direction of external force if the repulsive force  (equal in magnitude) is opposing it?

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source | link

ELECTRIC POTENTIAL AND WORK

a unit positive charge q is placed in an electric field caused due to a positive charge Q. q experiences force of repulsion (FR). we apply an external force (FEXT) opposite TO FR. the test charge moves in the direction opposite to electric field. work is done OPPOSITE TO the field. this work done is stored as potential difference.

now my doubt is below:-

we know that FR=-FEXT so two equal and opposite forces are acting on the charge q. it they are equal and opposite, they should cancel out each other know? then how is work done against the field.? why is the charge q moving in the direction of external force if the repulsive force(equal in magnitude) is opposing it?