Timeline for What is the physical meaning of the connection and the curvature tensor?
Current License: CC BY-SA 2.5
4 events
| when toggle format | what | by | license | comment | |
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| Jul 9, 2019 at 12:15 | comment | added | Andrew Steane | "no physical significance" is wrong: step on board a roller coaster or turntable and you will experience the physical significance right away. Even sitting in a chair you experience the physical significance of $\Gamma^a_{bc}$---or do all those high-school mechanics lessons with forces such as $m {\bf g}$ and pressures such as $m g h$ have "no physical significance"? | |
| Jan 3, 2011 at 2:22 | comment | added | Zo the Relativist | @Jeremy: If we're being pedantic, then <b>no</b> non-scalar is invariant--things that carry indices certainly change under a change of coordinates--they are <b>co</b>variant, not invariant. | |
| Jan 3, 2011 at 1:59 | comment | added | Jeremy | this is a very important point, and should be voted up! The connection has NO PHYSICAL significance. Although I wouldn't say because it is not a tensor, but rather because it is only dependent on coordinates, and is not invariant. | |
| Jan 2, 2011 at 18:49 | history | answered | Marek | CC BY-SA 2.5 |