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Qmechanic
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I was reading about how the Planck's Constant can be measured with LEDs, which made me think about this question.

The Heisenberg Uncertainty Principle states that: $$\Delta x \Delta p \ge {\hbar\over2}$$ a.k.a, there is always some uncertainty while measuring things.
This is a fundamental law. Nothing escapes it (as far as I know).

Now, when we are attempting to measure the Planck's Constant, wouldn't there be some uncertainty? This should mean that I can never be able to measure the Planck's Constant to full accuracy, ever. But if the amount of uncertainty depends on $\hbar$ (which is uncertain), doesn,tdoesn't this lead to uncertainty of uncertainty??

Note: I'm not a physicist. Just a physics enthusiast. Try not to get too technical, please.

I was reading about how the Planck's Constant can be measured with LEDs, which made me think about this question.

The Heisenberg Uncertainty Principle states that: $$\Delta x \Delta p \ge {\hbar\over2}$$ a.k.a, there is always some uncertainty while measuring things.
This is a fundamental law. Nothing escapes it (as far as I know).

Now, when we are attempting to measure the Planck's Constant, wouldn't there be some uncertainty? This should mean that I can never be able to measure the Planck's Constant to full accuracy, ever. But if the amount of uncertainty depends on $\hbar$ (which is uncertain), doesn,t this lead to uncertainty of uncertainty??

Note: I'm not a physicist. Just a physics enthusiast. Try not to get too technical, please.

I was reading about how the Planck's Constant can be measured with LEDs, which made me think about this question.

The Heisenberg Uncertainty Principle states that: $$\Delta x \Delta p \ge {\hbar\over2}$$ a.k.a, there is always some uncertainty while measuring things.
This is a fundamental law. Nothing escapes it (as far as I know).

Now, when we are attempting to measure the Planck's Constant, wouldn't there be some uncertainty? This should mean that I can never be able to measure the Planck's Constant to full accuracy, ever. But if the amount of uncertainty depends on $\hbar$ (which is uncertain), doesn't this lead to uncertainty of uncertainty?

Note: I'm not a physicist. Just a physics enthusiast. Try not to get too technical, please.

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Udit Dey
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Uncertainty in Uncertainty?

I was reading about how the Planck's Constant can be measured with LEDs, which made me think about this question.

The Heisenberg Uncertainty Principle states that: $$\Delta x \Delta p \ge {\hbar\over2}$$ a.k.a, there is always some uncertainty while measuring things.
This is a fundamental law. Nothing escapes it (as far as I know).

Now, when we are attempting to measure the Planck's Constant, wouldn't there be some uncertainty? This should mean that I can never be able to measure the Planck's Constant to full accuracy, ever. But if the amount of uncertainty depends on $\hbar$ (which is uncertain), doesn,t this lead to uncertainty of uncertainty??

Note: I'm not a physicist. Just a physics enthusiast. Try not to get too technical, please.