Timeline for Supercurrent dynamics
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 22, 2016 at 12:33 | vote | accept | Tejas Guruswamy | ||
| Mar 22, 2016 at 12:32 | comment | added | Tejas Guruswamy | Thanks, I appreciate your input, it has helped me think about this more clearly. | |
| Mar 22, 2016 at 0:15 | comment | added | CuriousOne | I don't think there is a complete theory that can model every possible situation. Self-organizing superconducting and non-superconducting domains will form near the critical field, I believe, and one would have to include fluctuations into the calculation. I have no experience with the more complex scenarios. My aim was to give you the most trivial case... that's not enough to discuss all possible thermodynamic configurations. | |
| Mar 21, 2016 at 13:11 | comment | added | Tejas Guruswamy | Is it true that the current is always within the penetration depth? | |
| Mar 18, 2016 at 21:31 | comment | added | CuriousOne | That there is no field in superconductors is incorrect, see en.wikipedia.org/wiki/London_penetration_depth. It's analogous to the skin effect in conductors. | |
| Mar 18, 2016 at 13:38 | comment | added | Tejas Guruswamy | Yes, I agree with you, maybe the explanation is same as in a normal conductor. But there is no magnetic field inside the superconductor -- so if we are only thinking about the microscopic dynamics, it's not the external magnetic field that's affecting the Cooper pairs -- it's the field created by the displacement/movement of the Cooper pairs around them? Hence they are "dragged along" with the current direction as a whole? Does that make any sense (it would seem to apply to normal conductors as well)? | |
| Mar 17, 2016 at 19:33 | comment | added | CuriousOne | "Normal charge carriers" aren't changing direction because of "scattering", either, an electron beam in vacuum can, for instance, form a nice ring in the presence of a magnetic field just fine. Charges are mainly following electromagnetic fields and the scattering part only causes dissipation. The wave function of a superconductor does the same, but it can avoid the dissipation altogether. Sounds a bit like a trick question... ? | |
| Mar 17, 2016 at 19:33 | answer | added | Thomas | timeline score: 3 | |
| Mar 17, 2016 at 19:11 | review | First posts | |||
| Mar 17, 2016 at 19:25 | |||||
| Mar 17, 2016 at 19:11 | history | asked | Tejas Guruswamy | CC BY-SA 3.0 |