Timeline for Trace of operator defined by two state vectors in Quantum Mechanics
Current License: CC BY-SA 3.0
5 events
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| Mar 11, 2016 at 22:27 | history | edited | Qmechanic♦ |
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| Mar 11, 2016 at 21:55 | vote | accept | Kamil | ||
| Mar 11, 2016 at 21:27 | comment | added | Prahar | Let $| \psi \rangle$ be a vector with components $a_i$ and $\langle \chi |$ be the vector with components $b_i$. Then, the square matrix $ ( | \psi \rangle\langle \chi |)$ has components $( | \psi \rangle\langle \chi |)_{ij} = a_i b_j$. Then, it's trace is $a_i b_i$ which is also equal to the inner product of the two vectors, namely $\langle \chi | \psi \rangle$. | |
| Mar 11, 2016 at 21:27 | answer | added | Evangeline A. K. McDowell | timeline score: 4 | |
| Mar 11, 2016 at 20:42 | history | asked | Kamil | CC BY-SA 3.0 |