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Mar 11, 2016 at 14:51 vote accept Erosennin
Mar 11, 2016 at 14:45 comment added fffred Whatever the weight of the car, it only depends on the affected area. If you make your car lightweight, maybe it would also dissipate very little the impact, thus the whole car would be affected, but I have no idea how the material properties change in that case.
Mar 11, 2016 at 14:40 comment added Erosennin Ok! And will this be different if it would be an inelastic collission? What I'm thinking is this: if the car was totally unaffected by the stone, because of its infinite mass, then how much glass would be destroyed would only depend on the material of the glass, velocity of glass, velocity of stone and weight of stone. Correct? But if the car was really lightweight, some momentum of the stone would be transfered to the whole car, and then the glass would not be as destroyed. Or?
Mar 11, 2016 at 14:31 comment added fffred No. That's exactly what I tried to explain. The interaction does not involve the whole car because the impact does not propagate anything further than centimetres. Only a small area around the impact zone matters. The overall car mass is irrelevant. Only the mass of the damaged zone. This zone (and its mass) will change depending on the properties of the windshield.
Mar 11, 2016 at 14:25 comment added Erosennin But upon impact, there will surely be released more energy if the car has higher mass?
Mar 11, 2016 at 11:33 history answered fffred CC BY-SA 3.0