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Mar 8, 2016 at 5:05 vote accept Aayush Agrawal
Mar 8, 2016 at 4:53 answer added hxri timeline score: 1
Mar 8, 2016 at 4:53 answer added Jahan Claes timeline score: 1
Mar 8, 2016 at 4:52 comment added march In the expression $x=ay^2/t$, $t$ (the stopping time) is implicitly a function of $a$, meaning that you cannot conclude from that expression that the stopping distance $x$ is proportional to $a$. The first expression is the correct one to use, because $v_0$ is a parameter in your problem, i.e. it is fixed by the initial conditions. That said, both expressions are correct; it just depends on what you're looking at that makes one or the other of the expressions the correct one to look at.
Mar 8, 2016 at 4:29 history asked Aayush Agrawal CC BY-SA 3.0