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Vacuum has both zero four-momentum and nonzero Does the vacuum in QFT have nonzero energy or not?

I have heard that in QFT, the vacuum has is postulated to have zero four-momentum:, $$P^\mu |\Omega \rangle = 0.$$ However, I also know that the vacuum hasit's supposed to have vacuum energy, i.e. $$ \langle \Omega | H | \Omega \rangle = E_0 \neq 0.$$ In textbooks, we patch up the latter equation by subtracting an infinite constant, and are told not to worry about it. In any case, the vacuum has to have zero four-momentum, as a fundamental axiom.

I am confused since a lot of answers on this site talk about vacuum energy as a real thing that has a definite value. If it's real, then why can we subtract it off to get $P^\mu |\Omega \rangle = 0$? If it's not real, why do we talk about it as if it is?

Vacuum has both zero four-momentum and nonzero vacuum energy?

I have heard that in QFT, the vacuum has zero four-momentum: $$P^\mu |\Omega \rangle = 0.$$ However, I also know that the vacuum has vacuum energy, i.e. $$ \langle \Omega | H | \Omega \rangle = E_0 \neq 0.$$ In textbooks, we patch up the latter equation by subtracting an infinite constant, and are told not to worry about it. In any case, the vacuum has to have zero four-momentum, as a fundamental axiom.

I am confused since a lot of answers on this site talk about vacuum energy as a real thing that has a definite value. If it's real, then why can we subtract it off to get $P^\mu |\Omega \rangle = 0$? If it's not real, why do we talk about it as if it is?

Does the vacuum in QFT have nonzero energy or not?

I have heard that in QFT, the vacuum has is postulated to have zero four-momentum, $$P^\mu |\Omega \rangle = 0.$$ However, I also know that it's supposed to have vacuum energy, $$ \langle \Omega | H | \Omega \rangle = E_0 \neq 0.$$ In textbooks, we patch up the latter equation by subtracting an infinite constant, and are told not to worry about it. In any case, the vacuum has to have zero four-momentum, as a fundamental axiom.

I am confused since a lot of answers on this site talk about vacuum energy as a real thing that has a definite value. If it's real, then why can we subtract it off to get $P^\mu |\Omega \rangle = 0$? If it's not real, why do we talk about it as if it is?

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I have heard that in QFT, the vacuum has zero four-momentum: $$P^\mu |\Omega \rangle = 0.$$ However, I also know that the vacuum has vacuum energy, i.e. $$ \langle \Omega | H | \Omega \rangle = E_0 \neq 0.$$ In textbooks, we patch up the latter equation by subtracting an infinite constant, and are told not to worry about it. In any case, the vacuum has to have zero four-momentum, as a fundamental axiom.

I am confused since a lot of answersa lot of answers on this site talk about vacuum energy as a real thing that has a definite value. If it's real, then why can we subtract it off to get $P^\mu |\Omega \rangle = 0$? If it's not real, why do we talk about it as if it is?

I have heard that in QFT, the vacuum has zero four-momentum: $$P^\mu |\Omega \rangle = 0.$$ However, I also know that the vacuum has vacuum energy, i.e. $$ \langle \Omega | H | \Omega \rangle = E_0 \neq 0.$$ In textbooks, we patch up the latter equation by subtracting an infinite constant, and are told not to worry about it. In any case, the vacuum has to have zero four-momentum, as a fundamental axiom.

I am confused since a lot of answers on this site talk about vacuum energy as a real thing that has a definite value. If it's real, then why can we subtract it off to get $P^\mu |\Omega \rangle = 0$? If it's not real, why do we talk about it as if it is?

I have heard that in QFT, the vacuum has zero four-momentum: $$P^\mu |\Omega \rangle = 0.$$ However, I also know that the vacuum has vacuum energy, i.e. $$ \langle \Omega | H | \Omega \rangle = E_0 \neq 0.$$ In textbooks, we patch up the latter equation by subtracting an infinite constant, and are told not to worry about it. In any case, the vacuum has to have zero four-momentum, as a fundamental axiom.

I am confused since a lot of answers on this site talk about vacuum energy as a real thing that has a definite value. If it's real, then why can we subtract it off to get $P^\mu |\Omega \rangle = 0$? If it's not real, why do we talk about it as if it is?

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knzhou
  • 105.1k
  • 24
  • 297
  • 494

Vacuum has both zero four-momentum and nonzero vacuum energy?

I have heard that in QFT, the vacuum has zero four-momentum: $$P^\mu |\Omega \rangle = 0.$$ However, I also know that the vacuum has vacuum energy, i.e. $$ \langle \Omega | H | \Omega \rangle = E_0 \neq 0.$$ In textbooks, we patch up the latter equation by subtracting an infinite constant, and are told not to worry about it. In any case, the vacuum has to have zero four-momentum, as a fundamental axiom.

I am confused since a lot of answers on this site talk about vacuum energy as a real thing that has a definite value. If it's real, then why can we subtract it off to get $P^\mu |\Omega \rangle = 0$? If it's not real, why do we talk about it as if it is?