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tmwilson26
tmwilson26
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I am a high school student and I would like to know why in a magnetic field the Force, F$F$, is equal to BIL x sin(theta)$BIL\sin(\theta)$, where theta$\theta$ represents the angle between the magnetic field and the current. I understand that F$F$ is proportional to B$B$, I$I$ and L$L$, but I do not understand the inclusion of sin (theta)$\sin (\theta)$. In other words, I would like to see a simple proof or explanation of why the effective length of the wire is L x sin(theta)$L \sin(\theta)$

I am a high school student and I would like to know why in a magnetic field the Force, F, is equal to BIL x sin(theta), where theta represents the angle between the magnetic field and the current. I understand that F is proportional to B, I and L, but I do not understand the inclusion of sin (theta). In other words, I would like to see a simple proof or explanation of why the effective length of the wire is L x sin(theta)

I am a high school student and I would like to know why in a magnetic field the Force, $F$, is equal to $BIL\sin(\theta)$, where $\theta$ represents the angle between the magnetic field and the current. I understand that $F$ is proportional to $B$, $I$ and $L$, but I do not understand the inclusion of $\sin (\theta)$. In other words, I would like to see a simple proof or explanation of why the effective length of the wire is $L \sin(\theta)$

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user63248
user63248

Magnetic force acting on a current carrying wire

I am a high school student and I would like to know why in a magnetic field the Force, F, is equal to BIL x sin(theta), where theta represents the angle between the magnetic field and the current. I understand that F is proportional to B, I and L, but I do not understand the inclusion of sin (theta). In other words, I would like to see a simple proof or explanation of why the effective length of the wire is L x sin(theta)